Why does this query write to the disk? - Mailing list pgsql-performance

From Nikolas Everett
Subject Why does this query write to the disk?
Date
Msg-id d4e11e980809181030t3f09db94vd5b69d7868271906@mail.gmail.com
Whole thread Raw
Responses Re: Why does this query write to the disk?
Re: Why does this query write to the disk?
List pgsql-performance
List,

I'm a bit confused as to why this query writes to the disk:
SELECT count(*)
FROM    bigbigtable
WHERE customerid IN (SELECT customerid FROM smallcustomertable)                                                        
AND x != 'special'                                                                               
AND y IS NULL 

It writes a whole bunch of data to the disk that has the tablespace where bigbigtable lives as well as writes a little data to the main disk.  It looks like its is actually WAL logging these writes.

Here is the EXPLAIN ANALYZE:
Aggregate  (cost=46520194.16..46520194.17 rows=1 width=0) (actual time=4892191.995..4892191.995 rows=1 loops=1)
  ->  Hash IN Join  (cost=58.56..46203644.01 rows=126620058 width=0) (actual time=2.938..4840349.573 rows=79815986 loops=1)
        Hash Cond: ((bigbigtable.customerid)::text = (smallcustomertable.customerid)::text)
        ->  Seq Scan on bigbigtable  (cost=0.00..43987129.60 rows=126688839 width=11) (actual time=0.011..4681248.143 rows=128087340 loops=1)
              Filter: ((y IS NULL) AND ((x)::text <> 'special'::text))
        ->  Hash  (cost=35.47..35.47 rows=1847 width=18) (actual time=2.912..2.912 rows=1847 loops=1)
              ->  Seq Scan on smallcustomertable  (cost=0.00..35.47 rows=1847 width=18) (actual time=0.006..1.301 rows=1847 loops=1)
Total runtime: 4892192.086 ms

Can someone point me to some documentation as to why this writes to disk?

Thanks,
Nik

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