Hi again I have this problem when I try to run this query, how can I rewrite
it for it to work.
SELECT o.item_order_num,SUM(o.item_quantity + o.item_product_id) As total,
o.item_status
FROM soko_product p, soko_ordered_item o
WHERE p.product_id = o.item_product_id
GROUP BY o.item_order_num
ORDER BY o.item_order_num;
Error: Attribute o.item_status must be GROUPED OR USE IN an aggregate
function
Please do advice thanks again
Kind regards
+-----------------------------------------------------+
| Martin W. Kuria (Mr.) martin.kuria@unon.org
+----------------------------------------------------+
>From: Christoph Haller <ch@rodos.fzk.de>
>To: pgsql-sql@postgresql.org
>CC: martinkuria@hotmail.com
>Subject: Re: [SQL] sub query
>Date: Wed, 17 Sep 2003 10:54:49 +0200
>
> >
> > > Hi I have this problem, when I try to run this query:
> > >
> > > SELECT MAX(d), host_position FROM (SELECT host_position,
> > > COUNT(host_position) as d FROM sss_host GROUP BY host_position) as
>e;
> > >
> > > am getting and ERROR: Attribute e.host_position must be GROUPed or
> > used in
> > > an aggregate function.
> > >
> > > Please to advice what could be the problem and how can I rewrite it
>to
> > work
> > > thanks in advance.
> > >
> > As the error message says: e.host_position must be GROUPed
> >
> > so (supposing you want a one row result showing the maximum count)
> >
> > SELECT MAX(e.d), e.host_position FROM (SELECT host_position,
> > COUNT(host_position) as d FROM sss_host GROUP BY host_position) as e
> > GROUP BY e.host_position ORDER BY 1 LIMIT 1;
> >
> > should match your intentions.
> >
>Just thought about another (less complex) way:
>
>SELECT COUNT(host_position), host_position FROM
>sss_host GROUP BY host_position ORDER BY 1 DESC LIMIT 1;
>
>Regards, Christoph
>
>
>
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