On Wed, 14 Mar 2001, G. Anthony Reina wrote:
> I think it would be something like:
> select distinct subject, arm, rep from circles_proc where rep = (select
> rep from circles_proc where 5 = count(cycle));
You're heading towards
SELECT distinct subject, arm, rep FROM circles_proc WHERE rep IN
(SELECT rep FROM circles_proc GROUP BY rep HAVING COUNT(rep)=5);
A possible variant would be
SELECT distinct subject, arm, rep FROM circles_proc c1 WHERE EXISTS
(SELECT rep FROM circles_proc c2 WHERE c1.rep=c2.rep GROUP BY reg HAVING
COUNT(rep)=5)
though w/a small set of test data, this seems less efficient.
There's also
SELECT DISTINCT subj, arm, rep FROM circles_proc c1 WHERE 5=
(SELECT COUNT(rep) FROM circles_proc c2 where c1.rep=c2.rep);
but, again, EXPLAIN thinks this will be less efficient.
Unless you get a great solution elsewhere :-), try indexing the fields
and testing the different queries above.
Good luck,
--
Joel Burton <jburton@scw.org>
Director of Information Systems, Support Center of Washington
