Re: Week of the Year? - Mailing list pgsql-sql

From John McKown
Subject Re: Week of the Year?
Date
Msg-id Pine.LNX.4.21.0008120846500.16858-100000@linux2.johnmckown.net
Whole thread Raw
In response to Week of the Year?  ("David Lloyd-Jones" <david.lloyd-jones@attcanada.ca>)
List pgsql-sql
Sorry,
I don't speak TCL or TK. I've got a book on it, but I haven't had any time
or pressing need to get familiar with it. I'm learning Python & PHP. Well,
at least I'm trying to whenever I can find a spare moment (which is rare).

On Sat, 12 Aug 2000, David Lloyd-Jones wrote:

> John,
> 
> Many thanks. What I actually need is to present the five weekdays of a week
> beginning with Sunday on a drop-down box in TCL; then have a person click on
> any day and get sales for that day, or on a thing at the bottom to get sales
> for the week
> 
> Do you TCL? Can you give me any clues on drop-down boxes, and how to get
> the -U, Linux week-of-the-year, into them?
> 
>                                           Best wishes,
> 
>                                                       -dlj.
> 
> Hey, I didn't know Prodigy still existed!
> 
> 
> 
> 
> 
> ----- Original Message -----
> From: "John McKown" <jmckown@prodigy.net>
> To: "David Lloyd-Jones" <david.lloyd-jones@attcanada.ca>
> Cc: <pgsql-sql@postgresql.org>
> Sent: Friday, August 11, 2000 10:55 PM
> Subject: Re: [SQL] Week of the Year?
> 
> 
> >
> > Try using the function date_part such as:
> >
> > select date_part('week',now());
> >
> > "and the days that are in that week" I guess want to answer a question
> > such as:
> > Given a date, what is first date in that same week, and what is the last
> > date in that week. There are a couple of approaches to this. My first was:
> >
> > select
> > to_date(date_part('year',now()),'YYYY')+(7*date_part('week',now()));
> >
> > and the above +6 to the the last day of the week. Another approach for
> > this same question is much simplier (if the question is indeed what you
> > are asking)
> >
> > select now()-date_part('dow',now());
> >
> > This last select gives the Sunday for the current week. To get the
> > Saturday, simply:
> >
> > select now()-date_part('dow',now())+6;
> >
> > Of course, replace the now() with whatever contains the date or timestamp.
> >
> > John McKown
> >
> > > I'm probably staring right at it. (One of the difficulties with RTFMing,
> is
> > > having too many docs!)
> > >
> > > Is there anything in the API that produces the week of the year, from 1
> to
> > > 52 or 53 depending on the week of the year, and the days that are in
> that
> > > week?
> > >
> > > Many thanks.
> > >
> > >                                           -dlj.
> > >
> > >
> > >
> >
> >
> 




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