On Mon, 18 Jun 2001, Tom Lane wrote:
> The Hermit Hacker <scrappy@hub.org> writes:
> > FROM note_links nl, notes n LEFT JOIN calendar c ON (n.nid = c.nid)
> > WHERE (n.type = 'A' OR n.type = 'N' OR n.type = 'H' OR n.type = 'C')
> > AND (nl.id = 15748 AND contact_lvl = 'company')
> > AND n.nid = nl.nid
> > ORDER BY start DESC;
>
> > Is there some way to write the above so that it evaluates:
> > first, so that it only has to do the LEFT JOIN on the *one* n.nid that is
> > returned, instead of the 86736 that are in the table?
>
> Try adding ... AND n.nid = 15748 ... to the WHERE. It's not very
> bright about making that sort of transitive-equality deduction for
> itself...
n.nid is the note id ... nl.id is the contact id ...
I'm trying to pull out all notes for the company with an id of 15748:
sepick=# select * from note_links where id = 15748; nid | id | contact_lvl | owner
-------+-------+-------------+-------84691 | 15748 | company | f
(1 row)
