Re: Variables - Mailing list pgsql-php

From Areski Belaid
Subject Re: Variables
Date
Msg-id OE35cxDRIME72AC1kox00001229@hotmail.com
Whole thread Raw
In response to [newbie] simple browse / edit form in PHP  ("Jules Alberts" <julesa@arbodienst-limburg.nl>)
List pgsql-php
Hi the Community,
 
A good exemple, it's always better that a long...
You must use the eval fonction. (www.php.net)
 
<?
$artist[]="Areski1";
$artist[]="Areski2";
$artist[]="Areski3";
$artist[]="Areski4";
 
$c0="Kiki1";
$c1="Kiki2";
$c2="Kiki3";
$c3="Kiki4";
 
for($count = 0; $count < sizeof($artist); $count++)
 {  
  eval( "echo \$c$count.\"<br>\";" ); //just to see no important
  eval( "\$c$count = \"$artist[$count]\";" ); 
  eval( "echo \"-->\".\$c$count.\"<br><br>\";" );//just to see no important
    }  
?>
 
I have the following variables: $c1 thru $c10.
  • I also have a FOR loop like this:
        for($count = 0; $count < sizeof($artist); $count++)
                { echo "<i>$artist[$count]</i><br>"; }
        // $artist is a list of ten (10) artist's names.
  • What I'm trying to do is something like this:  Combine the variables with the info inside the FOR loop:
        for($count = 0; $count < sizeof($artist); $count++)
                {  //Trying to assign the value of $c1, $c2, $c3, etc. using the value of the variable $count.
                   //But so far, it only processes the value of $count alone, and it ignores $c
                //The line below should read like this:  $c1 = $artist[0], next line:  $c2 = $artist[1], etc.
                        $c . $count+1 = $artist[$count];
                }

Help!!!

Julio Cuz, Jr.
Riverside Community College
jcuz@rccd.cc.ca.us

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