‐‐‐‐‐‐‐ Original Message ‐‐‐‐‐‐‐
On Wednesday, July 14th, 2021 at 1:14 PM, Thomas Kellerer <shammat@gmx.net> wrote:
> Laura Smith schrieb am 14.07.2021 um 13:22:
>
> > A bit of pl/pgsql writer's block going on here ...
> >
> > Postgres complains "RETURN cannot have a parameter in function returning set" in relation to the below. I don't
reallywant to have to "RETURNS TABLE" because that means I have to enumerate all the table columns.
> >
> > I'm sure I'm missing something simple here !
> >
> > CREATE OR REPLACE FUNCTION foobar(foo text,bar text) RETURNS SETOF bar AS $$
> >
> > DECLARE
> >
> > v_row bar%ROWTYPE;
> >
> > BEGIN
> >
> > insert into bar(f,b) values(foo,bar) returning * into v_row;
> >
> > return v_row;
> >
> > END;
> >
> > $$ language plpgsql;
>
> You need to use RETURN NEXT:
>
> CREATE OR REPLACE FUNCTION foobar(foo text,bar text)
>
> RETURNS SETOF bar
>
> AS $$
>
> DECLARE
>
> v_row bar%ROWTYPE;
>
> BEGIN
>
> insert into bar(f,b) values(foo,bar) returning * into v_row;
>
> return next v_row;
>
> END;
>
> $$
>
> language plpgsql;
>
> But you don't need PL/pgSQL for this or store the result in a variable:
>
> CREATE OR REPLACE FUNCTION foobar(foo text,bar text)
>
> RETURNS SETOF bar
>
> AS $$
>
> insert into bar(f,b) values(foo,bar)
>
> returning *;
>
> $$
>
> language sql;
Thank you for the tip on making it cleaner with sql. As you say, no real need for PL/pgSQL in this instance, but I'll
tryto remember RETURN NEXT in the future !
