Re: Query m:n-Combination - Mailing list pgsql-general

From Albe Laurenz
Subject Re: Query m:n-Combination
Date
Msg-id D960CB61B694CF459DCFB4B0128514C202A70D87@exadv11.host.magwien.gv.at
Whole thread Raw
In response to Query m:n-Combination  (Ludwig Kniprath <ludwig@kni-online.de>)
Responses Re: Query m:n-Combination  (Sam Mason <sam@samason.me.uk>)
List pgsql-general
Ludwig Kniprath wrote:
> A typical M:N-constellation, rivers in one table, communities in the
> other table, m:n-join-informations (which river is running in which
> community) in a third table.
>
> Table rivers:
> R_ID  R_Name
> 1     river_1
> 2     river_2
> 3     river_3
> 4     river_4
> 5     river_5
>
> Table communities :
> C_ID   C_Name
> 1      community_1
> 2      community_2
> 3      community_3
> 4      community_4
> 5      community_5
>
> Join-table
> mn_2_r_id   mn_2_c_id
> 1           1
> 1           2
> 1           3
> 1           4
> 2           1
> 3           2
> 3           5
> 4           3
> ...
>
> I want to know, which river is running through communities
> 1,2,3 *and* 4?
> You can see the solution by just looking at the data above (only
> "river_1" is running through all these countries), but how to
> query this by sql?

SELECT r.r_name FROM rivers AS r
  JOIN join-table j1 ON (r.r_id = j1.mn_2_r_id)
  JOIN join-table j2 ON (r.r_id = j2.mn_2_r_id)
  JOIN join-table j3 ON (r.r_id = j3.mn_2_r_id)
  JOIN join-table j4 ON (r.r_id = j4.mn_2_r_id)
WHERE j1.mn_2_c_id = (SELECT c_id FROM communities WHERE c_name = 'community_1')
  AND j2.mn_2_c_id = (SELECT c_id FROM communities WHERE c_name = 'community_2')
  AND j3.mn_2_c_id = (SELECT c_id FROM communities WHERE c_name = 'community_3')
  AND j4.mn_2_c_id = (SELECT c_id FROM communities WHERE c_name = 'community_4')

(untested)

Is that what you are looking for?

Yours,
Laurenz Albe

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