How to shorten a chain of logically replicated servers - Mailing list pgsql-general

From Mike Lissner
Subject How to shorten a chain of logically replicated servers
Date
Msg-id CAMp9=EzU5cBXSwaH=Somx6QTuH_pkN=pgYjSzZdVMs_+RnAveA@mail.gmail.com
Whole thread Raw
Responses Re: How to shorten a chain of logically replicated servers
Re: How to shorten a chain of logically replicated servers
List pgsql-general
Hi, I'm trying to figure out how to shorten a chain of logically
replicating servers. Right now we have three servers replicating like
so:

A --> B --> C

And I'd like to remove B from the chain of replication so that I only have:

A --> C

Of course, doing this without losing data is the goal. If the
replication to C breaks temporarily, that's fine, so long as all the
changes on A make it to C eventually.

I'm not sure how to proceed with this. My best theory is:

1. In a transaction, DISABLE the replication from A to B and start a
new PUBLICATION on A that C will subscribe to in step ③ below. The
hope is that this will simultaneously stop sending changes to B while
starting a log of new changes that can later be sent to C.

2. Let any changes queued on B flush to C. (How to know when they're
all flushed?)

3. Subscribe C to the new PUBLICATION created in step ①. Create the
subscription with copy_data=False. This should send all changes to C
that hadn't been sent to B, without sending the complete tables.

4. DROP all replication to/from B (this is just cleanup; the incoming
changes to B were disabled in step ①, and outgoing changes from B were
flushed in step ②).

Does this sound even close to the right approach? Logical replication
can be a bit finicky, so I'd love to have some validation of the
general approach before I go down this road.

Thanks everybody and happy new year,

Mike



pgsql-general by date:

Previous
From: Ron
Date:
Subject: Re: How to reset a server error '25P02 in_failed_sql_transaction'
Next
From: Matthias Apitz
Date:
Subject: Re: How to reset a server error '25P02 in_failed_sql_transaction'