Re: table returning function for each row in other resultset - Mailing list pgsql-general

From David G. Johnston
Subject Re: table returning function for each row in other resultset
Date
Msg-id CAKFQuwbh2sDFtfSupMz-f-3CFDCHaF1MzbaSCkJcNmAsAMG5Ug@mail.gmail.com
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In response to table returning function for each row in other resultset  (Niels Jespersen <NJN@dst.dk>)
Responses SV: table returning function for each row in other resultset
List pgsql-general
On Wed, Feb 3, 2021 at 8:01 AM Niels Jespersen <NJN@dst.dk> wrote:
Hello all

I have som data in a resultset. E.g:

id date_begin date_end      amount
1  2021-01-04 2021-02-06  100
2  2021-03-17 2021-05-11  234

I have a table returning function that can take one row and split it into constituent monthpieces and distribute amount proportionally.

select * from func(1, 2021-01-04, 2021-02-06, 100);
[...]
How can I accomplish this, please.

Lateral Join.

(not tested)
SELECT *
FROM resultset, func(id, date_begin, date_end, amount);

David J.

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