Even better:
SELECT COALESCE(value_of_interest, 'more friendly message') value_of_interest
From poly_table left outer join data_table one poly_table.common_id = data_table.common_id
--
Matheus de Oliveira
On Fri, Feb 3, 2012 at 1:05 PM, Matheus de Oliveira
<matioli.matheus@gmail.com> wrote:
Try that:
SELECT address, CASE WHEN value_of_interest IS NULL THEN 'more friendly message' ELSE value_of_interest END value_of_interest
From poly_table left outer join data_table one poly_table.common_id = data_table.common_id
--
Matheus de OliveiraOn Fri, Feb 3, 2012 at 10:45 AM, John Morgan
<jdmorgan@unca.edu> wrote:
Hello,
I am doing a left outer join between a polygon table and a data table.
Everything
returns fine from this join as expected. However, there are cases where
there isn?t data for a given polygon and this return as the expected null
in the result set. I would like to utilize something like a case statement
to catch the nulls and return a ?more friendly? message. I have tried
unsuccessfully to use the following logic:
*Select case value_of_interest null then ?more friendly message? else
value_of_interest end*
*From poly_table left outer join data_table one poly_table.common_id =
data_table.common_id*
If someone could let me know where I am going wrong it would be greatly
appreciated.
Cheers,
Derek
