Re: calling procedures is slow and consumes extra much memory againstcalling function - Mailing list pgsql-hackers

From Pavel Stehule
Subject Re: calling procedures is slow and consumes extra much memory againstcalling function
Date
Msg-id CAFj8pRAQtxV17MpuRr4BPKtOxghnicpREi5=gyu96mvCgyK+sg@mail.gmail.com
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In response to Re: calling procedures is slow and consumes extra much memory againstcalling function  (Amit Khandekar <amitdkhan.pg@gmail.com>)
Responses Re: calling procedures is slow and consumes extra much memory against calling function
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st 17. 6. 2020 v 7:52 odesílatel Amit Khandekar <amitdkhan.pg@gmail.com> napsal:
On Wed, 10 Jun 2020 at 17:12, Pavel Stehule <pavel.stehule@gmail.com> wrote:
> st 10. 6. 2020 v 12:26 odesílatel Amit Khandekar <amitdkhan.pg@gmail.com> napsal:
>> Could you show an example testcase that tests this recursive scenario,
>> with which your earlier patch fails the test, and this v2 patch passes
>> it ? I am trying to understand the recursive scenario and the re-use
>> of expr->plan.
>
>
> it hangs on plpgsql tests. So you can apply first version of patch
>
> and "make check"

I could not reproduce the make check hang with the v1 patch. But I
could see a crash with the below testcase. So I understand the purpose
of the plan_owner variable that you introduced in v2.

Consider this recursive test :

create or replace procedure p1(in r int) as $$
begin
   RAISE INFO 'r : % ', r;
   if r < 3 then
      call p1(r+1);
   end if;
end
$$ language plpgsql;

do $$
declare r int default 1;
begin
    call p1(r);
end;
$$;

In p1() with r=2, when the stmt "call p1(r+1)" is being executed,
consider this code of exec_stmt_call() with your v2 patch applied:
if (expr->plan && !expr->plan->saved)
{
   if (plan_owner)
      SPI_freeplan(expr->plan);
   expr->plan = NULL;
}

Here, plan_owner is false. So SPI_freeplan() will not be called, and
expr->plan is set to NULL. Now I have observed that the stmt pointer
and expr pointer is shared between the p1() execution at this r=2
level and the p1() execution at r=1 level. So after the above code is
executed at r=2, when the upper level (r=1) exec_stmt_call() lands to
the same above code snippet, it gets the same expr pointer, but it's
expr->plan is already set to NULL without being freed. From this
logic, it looks like the plan won't get freed whenever the expr/stmt
pointers are shared across recursive levels, since expr->plan is set
to NULL at the lowermost level ? Basically, the handle to the plan is
lost so no one at the upper recursion level can explicitly free it
using SPI_freeplan(), right ? This looks the same as the main issue
where the plan does not get freed for non-recursive calls. I haven't
got a chance to check if we can develop a testcase for this, similar
to your testcase where the memory keeps on increasing.

This is a good consideration.  

I am sending updated patch

Pavel



-Amit
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