I wrote:
> I assume that's because it can be certain at compile time that, since
> both buff and buff2 are local, nothing else is going to modify the
> source string (without some stack smashing, anyway).
Ugh. Of course, they're not local: they're malloc'd; however it's
still reasonable to assume that (since the pointers aren't passed
anywhere) the buffers are untouched elsewhere, unless other threads
are misbehaving.
Geoff
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