On Tue, Nov 7, 2017 at 3:43 AM, Tom Lane <tgl@sss.pgh.pa.us> wrote:
> The size of the overhead in this case implies that gettimeofday() is doing
> a kernel call, which I wouldn't really have expected on any modern Linux
> kernel. What hardware is this on? Is there virtualization involved?
A virtual server with no vDSO, I'll bet. Like this:
https://stackoverflow.com/questions/42622427/gettimeofday-not-using-vdso
--
Thomas Munro
http://www.enterprisedb.com
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