Re: != ANY(array) does not behave as expected - Mailing list pgsql-general
On Fri, Dec 7, 2018 at 5:21 AM Thomas Kellerer <spam_eater@gmx.net> wrote:
Thomas Kellerer schrieb am 07.12.2018 um 13:48:
> Chris Wilson schrieb am 07.12.2018 um 13:39:
>> However, if we try to invert it by using the != operator, then we get unexpected results:
>>
>> select * from foo where id NOT IN (1, 2); /* returns row 3 only, as expected */
>> select * from foo where id != ANY (ARRAY[1, 2]); /* returns all rows, unexpected */
>
> id <> ANY (...) means: return "true" if at least one of the elements is not equal to the value on the left side.
>
> What you are looking for is the ALL operator
>
> select *
> from foo
> where id <> ALL (ARRAY[1, 2]);
>
> That is essentially the equivalent to NOT IN
See here for a longer explanation:
https://stackoverflow.com/a/10675636
You can also just do this:
select * from foo where NOT id = ANY (ARRAY[1, 2]);
Cheers,
Ken
-- Ken
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