The following script creates a partition table with a foreign key and works fine on PostgreSQL 14:
begin; create table a(id int primary key); create table b(id int primary key, a_id int not null references a(id)) partition by range(id); create table b_default(like b including defaults including constraints); alter table b attach partition b_default default; alter table b disable trigger all; commit;
On PostgresSQL 15, it fails on DISABLE TRIGGER ALL:
ERROR: trigger "RI_ConstraintTrigger_c_20196703" for table "b_default" does not exist
It seems to use a wrong trigger name. In this case, RI_ConstraintTrigger_c_20196703 is the name of a trigger defined on the parent table b.
