select json_object_agg(gid, y) from ( select gid, jsonb_agg(row_to_json(chat)) y from chat group by gid ) x; 01.01.2018 16:41, Alexander Farber пишет: I have prepared a simple SQL Fiddle demonstrating my problem: http://sqlfiddle.com/#!17/2c9c5/1
I have prepared a simple SQL Fiddle demonstrating my problem: http://sqlfiddle.com/#!17/2c9c5/1
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