> Deferrability is a property of a constraint, not an index
Yes, but creating a unique constraint implicitly creates an index, and
creating a unique index implicitly creates a constraint. So I'm
wondering whether I can create a pair where the index is partial and
the constraint is deferrable. It sounds like the answer is no? Is
there a workaround where I first create one and then alter the other
one?
Thanks,
Paul
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Pulchritudo splendor veritatis.
