Re: sql - Mailing list pgsql-sql

Hi...
I tried this its working.. can u please check this.

select count(*) as all, sum(decode(entry_user_id,'VC',1)) as
entry_user_id,sum(decode(entry_user_id,'VE',1)) as VE
,sum(decode(entry_user_id,CV,1))as
CV,sum(decode(entry_user_id,'SC',1))as SC from vigilance_master;


regards
penchal

-----Original Message-----
From: pgsql-sql-owner@postgresql.org
[mailto:pgsql-sql-owner@postgresql.org] On Behalf Of Karthikeyan
Sundaram
Sent: Tuesday, February 06, 2007 12:47 PM
To: shyjukoyyam@gmail.com; pgsql-sql@postgresql.org
Subject: Re: [SQL] sql

try this:

select entry_user_id, sum(decode(entry_user_id,'VC',1,0) as vc,            sum(decode(entry_user_id,'VE',1,0) as ve,
       sum(decode(entry_user_id,'CV',1,0) as cv,            sum(decode(entry_user_id,'SC',1,0) as SC 
from vigilance_master group
where entry_user_id=78
group by entry_user_id



>From: "Shyju Narayanan" <shyjukoyyam@gmail.com>
>To: pgsql-sql@postgresql.org
>Subject: [SQL] sql
>Date: Fri, 2 Feb 2007 13:09:09 +0530
>
>Hi All
>
>this is my table ;
>| ID    |entry_user_id_int  | category_id_chv |
>----------------------------------------------
>| 1        |        78            |    CV              |
>----------------------------------------------
>| 2        |        78            |    VC              |
>----------------------------------------------
>| 3        |        78            |    CV            |
>----------------------------------------------
>| 4        |        78            |    CV            |
>----------------------------------------------
>| 5        |        78            |    CV            |
>----------------------------------------------
>| 6        |        78            |    CV            |
>----------------------------------------------
>| 7        |        78            |    CV            |
>----------------------------------------------
>| 8        |        78            |    CV            |
>----------------------------------------------
>| 9        |        78            |    VE            |
>----------------------------------------------
>| 10    |        78            |    CV            |
>----------------------------------------------
>| 11    |        78            |    SC            |
>----------------------------------------------
>
>WHEN "select entry_user_id_int, category_id_chv,count(category_id_chv)
from
>vigilance_master group by category_id_chv,entry_user_id_int having"
>entry_user_id_int=78
>result is :
>
>ID   entry_user_id_int  category_id_chv count
>
>1        78                       VC                     1
>2        78                       VE                     1
>3        78                       CV                     8
>4        78                       SC                     1
>
>BUT I NEED THE RESULT AS
>entry_user_id_int     COUNT(VC)  COUNT(VE)  COUNT(CV)   COUNT(SC)
TOTAL
>78        1 1 8 1 11

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