This works for me:
...like ''%'' || b.vendor_name || ''%''
Looks like you have too many single quotes...
Rgds,
Bret
> -----Original Message-----
> From: pgsql-novice-owner@postgresql.org
> [mailto:pgsql-novice-owner@postgresql.org] On Behalf Of Paul Murphy
> Sent: Thursday, January 20, 2005 11:21 AM
> To: pgsql-novice@postgresql.org
> Subject: [NOVICE] Problems with PL/pgSQL and LIKE statement
>
> Hi all,
>
> I'm writing a function that basically returns all of the URLs
> that are like (in the SQL sense of LIKE) a string that I
> supply. I can't seem to get the correct arrangement of
> percent symbols and quotes to get the statement to run correctly.
>
> Here's a simplified version of what I'm trying to do...
>
> CREATE OR REPLACE FUNCTION get_urls_like(varchar)
> RETURNS varchar AS
> 'DECLARE
> param ALIAS FOR $1;
> entry varchar;
> BEGIN
> FOR entry IN SELECT url AS url
> FROM urls u
> WHERE url LIKE ''''%'''' || param || ''''%''''
> LOOP
> RETURN NEXT entry;
> END LOOP;
> RETURN;
> END;'
> LANGUAGE 'plpgsql' STABLE;
>
>
> Any help gratefully received. I've tried various combinations
> of percent signs and single quotes and usually end up with
> errors like the following.
>
> ERROR: operator is not unique: "unknown" % "unknown"
> HINT: Could not choose a best candidate operator. You may
> need to add explicit type casts.
> CONTEXT: PL/pgSQL function "get_classifications_like" line 6
> at for over select rows
>
> Cheers
>
> Paul
>
> Paul Murphy
> Senior Software Engineer
> Packet Dynamics Ltd
> tel: +44 (0)1506 426 976
> fax: +44 (0)1506 418 844
> pmurphy at bloxx dot com
> Call 08700 4 BLOXX or visit www.bloxx.com
>
>
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