Re: libpq: PQexecParams, binaryFormat and float - Mailing list pgsql-interfaces
| From | Richard Frankland |
|---|---|
| Subject | Re: libpq: PQexecParams, binaryFormat and float |
| Date | |
| Msg-id | 959570.69903.qm@web32613.mail.mud.yahoo.com Whole thread Raw |
| In response to | libpq: PQexecParams, binaryFormat and float ("Sun, Way" <Way.Sun@sciatl.com>) |
| List | pgsql-interfaces |
Hi, This is my first reply/post to postgres forums. I hope I'm doing it OK.
If not, please help.
So, onto how I see the problem and a possible solution.
As Tom Lane pointed out. Using a "union" is another solution to this problem.
Here is a simple testing program and output:
#include <stdio.h>
/* for ntohl/htonl */
#include <netinet/in.h>
void show_hex (void * vptr) {
unsigned char * xptr;
int k;
/* display each byte in heX */
xptr = (unsigned char *)vptr;
for (k=0; k<4; k++)
{
printf("%.2X ", *(xptr+k));
}
printf("\n");
}
int
main(int argc, char **argv)
{
float starting_value = 1.23;
float loadavg;
unsigned long reversed_float;
/* prove we really are starting with 1.23 */
printf( "%f \n", starting_value);
show_hex(&starting_value);
/* see man page for return type of htonl() */
reversed_float = htonl(starting_value);
show_hex(&reversed_float);
/* implicit conversion shown explicitly (i.e. has no effect) */
reversed_float = htonl((long)starting_value);
show_hex(&reversed_float);
/* and another implicit conversion */
loadavg = reversed_float; //htonl(starting_value);
show_hex(&loadavg);
/* again, shown explicitly */
loadavg = (float)(unsigned long)16777216; //htonl(starting_value);
show_hex(&loadavg);
loadavg = (float)(unsigned long)htonl((long)starting_value); //htonl(starting_value);
show_hex(&loadavg);
/* show what was stored into loadavg */
printf( "%f \n", loadavg);
/* show this is the same as the original problem */
loadavg = htonl(1.23);
printf( "%f \n", loadavg);
/* A (not the only one) correct solution */
/* Casting a pointer: */
/* address of source */
/* | */
/* pointer to UNSIGNED type | */
/* | | */
/* dereference pointer | | */
/* | | | */
/* | | | */
/* | | | */
reversed_float = htonl(*(unsigned long *)&starting_value);
show_hex(&reversed_float);
/*
* paramValues[0] = (unsigned char *) &reversed_float;
*/
}
------------------------------------------------------
$ ./tst
1.230000
A4 70 9D 3F
00 00 00 01
00 00 00 01
00 00 80 4B
00 00 80 4B
16777216.000000
16777216.000000
3F 9D 70 A4
$
"Sun, Way" <Way.Sun@sciatl.com> wrote:
Boardwalk for $500? In 2007? Ha!
Play Monopoly Here and Now (it's updated for today's economy) at Yahoo! Games.
If not, please help.
So, onto how I see the problem and a possible solution.
As Tom Lane pointed out. Using a "union" is another solution to this problem.
Here is a simple testing program and output:
#include <stdio.h>
/* for ntohl/htonl */
#include <netinet/in.h>
void show_hex (void * vptr) {
unsigned char * xptr;
int k;
/* display each byte in heX */
xptr = (unsigned char *)vptr;
for (k=0; k<4; k++)
{
printf("%.2X ", *(xptr+k));
}
printf("\n");
}
int
main(int argc, char **argv)
{
float starting_value = 1.23;
float loadavg;
unsigned long reversed_float;
/* prove we really are starting with 1.23 */
printf( "%f \n", starting_value);
show_hex(&starting_value);
/* see man page for return type of htonl() */
reversed_float = htonl(starting_value);
show_hex(&reversed_float);
/* implicit conversion shown explicitly (i.e. has no effect) */
reversed_float = htonl((long)starting_value);
show_hex(&reversed_float);
/* and another implicit conversion */
loadavg = reversed_float; //htonl(starting_value);
show_hex(&loadavg);
/* again, shown explicitly */
loadavg = (float)(unsigned long)16777216; //htonl(starting_value);
show_hex(&loadavg);
loadavg = (float)(unsigned long)htonl((long)starting_value); //htonl(starting_value);
show_hex(&loadavg);
/* show what was stored into loadavg */
printf( "%f \n", loadavg);
/* show this is the same as the original problem */
loadavg = htonl(1.23);
printf( "%f \n", loadavg);
/* A (not the only one) correct solution */
/* Casting a pointer: */
/* address of source */
/* | */
/* pointer to UNSIGNED type | */
/* | | */
/* dereference pointer | | */
/* | | | */
/* | | | */
/* | | | */
reversed_float = htonl(*(unsigned long *)&starting_value);
show_hex(&reversed_float);
/*
* paramValues[0] = (unsigned char *) &reversed_float;
*/
}
------------------------------------------------------
$ ./tst
1.230000
A4 70 9D 3F
00 00 00 01
00 00 00 01
00 00 80 4B
00 00 80 4B
16777216.000000
16777216.000000
3F 9D 70 A4
$
"Sun, Way" <Way.Sun@sciatl.com> wrote:
Hi,I'm having trouble inserting a float into pg using binary format.Hope someone on the list can help me point out what I'm doing wrong....float loadavg;loadavg = htonl(1.23);paramValues[0] = (char *) &loadavg
paramLengths[0] = sizeof(loadavg);
paramFormats[0] = 1;res = PQexecParams(conn,
"INSERT INTO cpu (loadavg) VALUES ($1::real)",
1,
NULL,
paramValues,
paramLengths,
paramFormats,
1);From psql, select returns the value as 1.20765e-38 instead of 1.23.....:(ThanksWay
- - - - - Appended by Scientific Atlanta, a Cisco company - - - - -
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Boardwalk for $500? In 2007? Ha!
Play Monopoly Here and Now (it's updated for today's economy) at Yahoo! Games.
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