Sorry, I forgot a key clause there:
Greg Stark <gsstark@MIT.EDU> writes:
> select w8.wid,
> w8.variant,
> w8.num_variants,
> sum_text(w8.unicode) as unicodes,
> sum_text(w8.pinyin) as pinyins
> from (
> select wid,variant,
> from words
> where (sequence = 0 and pinyin = 'zheng4')
> OR (sequence = 1 and pinyin like 'ji_')
> OR (sequence = 2 and pinyin like 'guan_')
> OR (sequence = 3 and pinyin like 'kai_')
> OR (sequence = 4 and pinyin like 'fang_')
> OR (sequence = 5 and pinyin like 'xi_')
> OR (sequence = 6 and pinyin like 'tong_')
> OR (sequence = 7 and pinyin like 'fu_')
> group by wid,variant
> having count(*) = 8
> ) as w
> join words as w8 using (wid,variant)
where w8.sequence = 8
Or perhaps that ought to be
join words as w8 on ( w8.wid=w.wid
and w8.variant=w.variant
and w8.sequence = 8)
or even
join (select * from words where sequence = 8) as w8 using (wid,variant)
I think they should all be equivalent though.
--
greg
