Joel Jacobson <joel@gluefinance.com> writes:
> It's not possible to use a plain recursive query to do the trick (due
> to 'i' bidirectional dependencies and dependency loops).
Well I came up with that while working on some extension related fun
dependency problems, I guess it could help you:
~:5490=# WITH RECURSIVE depends AS (select 16385 as nsp, objid, refobjid, array[refobjid] as deps from pg_depend where
refobjid= 16854 and deptype != 'p'UNION ALLselect p.nsp, p.objid, d.refobjid, deps || d.refobjid from pg_depend d JOIN
dependsp ON d.objid = p.objid where d.deptype != 'p' and not d.refobjid = any(deps)
)
select * from depends; nsp | objid | refobjid | deps
-------+-------+----------+--------------------16385 | 16851 | 16854 | {16854}16385 | 16852 | 16854 |
{16854}16385| 16853 | 16854 | {16854}16385 | 16851 | 2200 | {16854,2200}16385 | 16852 | 2200 |
{16854,2200}16385| 16852 | 16851 | {16854,16851}16385 | 16853 | 2200 | {16854,2200}16385 | 16852 | 2200 |
{16854,16851,2200}16385| 16852 | 16851 | {16854,2200,16851}
(9 rows)
Regards,
--
Dimitri Fontaine
http://2ndQuadrant.fr PostgreSQL : Expertise, Formation et Support
