Richard Albright <ralbright@insiderscore.com> writes:
> you could use distinct on
>
> select distinct on (fs.film.title, fs.film.year ) title, year
> from fs.film left join fs.star on fs.film.id = fs.star.film
> where fs.star.last = 'Sheen';
Thanks, I didn't know about "distinct on". This version uses the
primary (surrogage) key:
select distinct on (fs.film.id) fs.film.title, fs.film.year from fs.film left join fs.star on fs.film.id = fs.star.film
wherefs.star.last = 'Sheen';
DES
--
Dag-Erling Smørgrav - des@des.no
