Re: [SOLVED] UPDATE with WHERE clause on joined table - Mailing list pgsql-sql

From Fabian Peters
Subject Re: [SOLVED] UPDATE with WHERE clause on joined table
Date
Msg-id 7ECE6348-3F8E-4F34-BE48-D7F416EE6F46@e-lumo.com
Whole thread Raw
In response to Re: UPDATE with WHERE clause on joined table  (Erik Jones <erik@myemma.com>)
List pgsql-sql
Am 29.07.2006 um 01:30 schrieb Erik Jones:

> Fabian Peters wrote:
>> Hi,
>>
>> I'm only very rarely using SQL, so please forgive me if I show any  
>> obvious signs of ignorance...
>>
>> I've got three tables "customer", "address" and "country". I want  
>> to set the "language" attribute on "customer" on rows returned by  
>> a SELECT such as this:
>>
>> SELECT title, first_names, last_name, email, language,  
>> country.country_name FROM ((customer JOIN address ON customer.eoid  
>> = address.eoid_customer) JOIN country ON address.eoid_country =  
>> country.eoid) WHERE email LIKE '%.es' AND country.country_name =  
>> 'SPAIN';
>>
>> That is, I want to set the "language" to 'Spanish' where the  
>> "customer.email" is like '%.es' and where "country.country_name"  
>> is 'SPAIN'.
>>
>> I've tried all sorts of places to put the JOIN and the WHERE  
>> clauses within the UPDATE statement, but I just don't get it.
>>
>> I'd be most grateful for any help...
>>
>> TIA
>>
>> Fabian
>>
>> P.S.: One of my sorry attempts looked like this - which updates  
>> all rows in "customer" so I figure the WHERE clause is not where  
>> it should be:
>>
>> UPDATE customer SET language = 'Spanish' FROM ((customer AS  
>> customer_address JOIN address ON customer_address.eoid =  
>> address.eoid_customer) JOIN country ON address.eoid_country =  
>> country.eoid) WHERE customer.email LIKE '%.es' AND  
>> country.country_name = 'SPAIN');
> The FROM clause is where you put relations other than the one you   
> are updating.  Try this:
>
> UPDATE customer
> SET language='Spanish'
> FROM address ad, country co
> WHERE customer.eoid=ad.eoid_customer AND ad.eoid_country=co.eoid
>    AND co.country_name='SPAIN' AND customer.email LIKE '%.es';
>
> Note that for demonstration purposes I've aliased the join tables  
> and that (unfortunately) you can't alias the update table.
>
> erik jones <erik@myemma.com>
> software development
> emma(r)

Erik, thanks a lot! Works like a charm and is so much more concise  
than my attempts.

cheers

Fabian



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