--that's close. but i need the '0' in the field between the
year and the quarter.
--all of this because a company want's fixed length columns.
--i was reading about something like this:
[example]
select to_char(to_date('05/21/1998'),'Q') from dual
[/example]
--trying to modify it somehow ...
--thanks!
-X
How about:
SELECT date_part('y', datefield) || date_part('qtr', datefield)
FROM tablename;
Howdy:
I'm running Postgres 7.1.3 on RedHat Linux 7.2, kernel version
2.4.7 rel 10.
I've created a table which includes the date. I have been instructed
to map the date into something that reflects the quarter of the year
on the fly (somewhere in the script). For example:
(currently) date: (needed) quarter:
2001-02-26 200101
1998-05-12 199802
803-11-11 80304
I was thinking I'd have to use something like a case statement, but
I don't know enough about SQL to do something like that. Somehow, I
had the notion that if it were possible to write 'if-then-else' loops
I could probably do it.
Is there such a mechanism to do what is being asked of me?
Thanks!
-X
