Re: Function returns error (view) - Mailing list pgsql-sql
From | Professor Flávio Brito |
---|---|
Subject | Re: Function returns error (view) |
Date | |
Msg-id | 6a5e3a6f0802261020o51327bceof4845c47ae1b099d@mail.gmail.com Whole thread Raw |
In response to | Re: Function returns error (view) ("Bart Degryse" <Bart.Degryse@indicator.be>) |
Responses |
Re: Function returns error (view)
|
List | pgsql-sql |
Hi
After I did it I received it
ERROR: set-valued function called in context that cannot accept a set
SQL state: 0A000
Context: PL/pgSQL function "seach_password(" line 14 at return next
Error at WHERE login= USER_FOO ??
Thanks for your help
Flávio
After I did it I received it
ERROR: set-valued function called in context that cannot accept a set
SQL state: 0A000
Context: PL/pgSQL function "seach_password(" line 14 at return next
Error at WHERE login= USER_FOO ??
Thanks for your help
Flávio
2008/2/26, Bart Degryse <Bart.Degryse@indicator.be>:
I think you have a quoting problemYou want something likeWHERE login= 'Flavo'But you're making something likeWHERE login = FlavoSomething like this should work...CREATE OR REPLACE FUNCTION seach_password(USER_FOO IN table_user.login%TYPE)
RETURNS SETOF vw_change_password AS
$BODY$
DECLARE
r vw_change_password%ROWTYPE;
USER_FOO alias for $1;
BEGINFOR r IN (
SELECT u.cod_user, u.user_name, u.openpsw, t.user_password, t.end, t.validate, t.date_add, t.user_time, u.ok
FROM usuario u, change_user_password t
WHERE u.cod_user = t.cod_user AND t.cod_user IN (SELECT cod_user FROM table_user WHERE login= USER_FOO))LOOP
RETURN NEXT r;
END LOOP;
IF NOT FOUND THEN
RAISE EXCEPTION 'USER not found (%)', USER_FOO;
END IF;
RETURN;
END
$BODY$
LANGUAGE 'plpgsql' VOLATILE;
>>> "Professor Flávio Brito" <prof.flaviobrito@gmail.com> 2008-02-26 17:32 >>>
Hi
Don't know why I can't receive a return like my view fields (I'm newbie in plpgsql). Postgresql returns me a erro . How can I received a answer like my view structure?
When I Test my view I receive
SELECT seach_password('user_login_foo')
My view returns me
25746;"MARCELO ";"bio1";"bio1";"2008-02-19";"FALSE";"2008-02-12";"2008-02-12 12:51:40.229282";"TRUE"
30356;"JOSE DE JESUS ";"977";"377";"2008-02-19";"FALSE";"2008-02-12";"2008-02-12 12:52:19.688381";"TRUE"
It's OK
but when I use function it returns me
ERROR: column "user_login_foo" does not exist
SQL state: 42703
Context: PL/pgSQL function "search_password" line 14 at for over execute statement
Where is my fault?
Thanks
Flávio
*************************************************************************************************************
vw_change_password attributes
cod_user integer,
user_name varchar(150),
openpsw varchar (32),
user_password varchar (50),
end timestamp,
validate boolean,
date_add timestamp,
user_time timestamp,
ok boolean
CREATE OR REPLACE FUNCTION seach_password(USER_FOO varchar(100))
RETURNS SETOF vw_change_password AS
$BODY$
DECLARE
r vw_change_password%ROWTYPE;
USER_FOO alias for $1;
sql TEXT;
BEGIN
sql= 'SELECT u.cod_user, u.user_name, u.openpsw, t.user_password, t.end, t.validate, t.date_add, t.user_time, u.ok
FROM usuario u, change_user_password t
WHERE u.cod_user = t.cod_user AND t.cod_user
IN
(SELECT cod_user
FROM table_user
WHERE login='||USER_FOO||')';
FOR r IN EXECUTE sql
LOOP
RETURN NEXT r;
END LOOP;
IF NOT FOUND THEN
RAISE EXCEPTION 'USER not found', USER_FOO;
END IF;
RETURN;
END
$BODY$
LANGUAGE 'plpgsql' VOLATILE;