Slow deleting tables with foreign keys - Mailing list pgsql-performance

From Jeremy Palmer
Subject Slow deleting tables with foreign keys
Date
Msg-id 666FB8D75E95AE42965A0E76A5E5337E06DCBABE90@prdlsmmsg01.ad.linz.govt.nz
Whole thread Raw
Responses Re: Slow deleting tables with foreign keys  (Bob Lunney <bob_lunney@yahoo.com>)
Re: Slow deleting tables with foreign keys  (Robert Haas <robertmhaas@gmail.com>)
List pgsql-performance
Hi All,

I'm trying to delete one row from a table and it's taking an extremely long time. This parent table is referenced by
othertable's foreign keys, but the particular row I'm trying to delete is not referenced any other rows in the
associativetables. This table has the following structure: 

CREATE TABLE revision
(
  id serial NOT NULL,
  revision_time timestamp without time zone NOT NULL DEFAULT now(),
  start_time timestamp without time zone NOT NULL DEFAULT clock_timestamp(),
  schema_change boolean NOT NULL,
  "comment" text,
  CONSTRAINT revision_pkey PRIMARY KEY (id)
)
WITH (
  OIDS=FALSE
);

This table is referenced from foreign key by 130 odd other tables. The total number of rows from these referencing
tablesgoes into the hundreds of millions. Each of these tables has been automatically created by script and has the
same_revision_created, _revision_expired fields, foreign keys and indexes. Here is an example of one: 

CREATE TABLE table_version.bde_crs_action_revision
(
  _revision_created integer NOT NULL,
  _revision_expired integer,
  tin_id integer NOT NULL,
  id integer NOT NULL,
  "sequence" integer NOT NULL,
  att_type character varying(4) NOT NULL,
  system_action character(1) NOT NULL,
  audit_id integer NOT NULL,
  CONSTRAINT "pkey_table_version.bde_crs_action_revision" PRIMARY KEY (_revision_created, audit_id),
  CONSTRAINT bde_crs_action_revision__revision_created_fkey FOREIGN KEY (_revision_created)
      REFERENCES table_version.revision (id) MATCH SIMPLE
      ON UPDATE NO ACTION ON DELETE NO ACTION,
  CONSTRAINT bde_crs_action_revision__revision_expired_fkey FOREIGN KEY (_revision_expired)
      REFERENCES table_version.revision (id) MATCH SIMPLE
      ON UPDATE NO ACTION ON DELETE NO ACTION
)
WITH (
  OIDS=FALSE
);
ALTER TABLE table_version.bde_crs_action_revision OWNER TO bde_dba;
ALTER TABLE table_version.bde_crs_action_revision ALTER COLUMN audit_id SET STATISTICS 500;


CREATE INDEX idx_crs_action_audit_id
  ON table_version.bde_crs_action_revision
  USING btree
  (audit_id);

CREATE INDEX idx_crs_action_created
  ON table_version.bde_crs_action_revision
  USING btree
  (_revision_created);

CREATE INDEX idx_crs_action_expired
  ON table_version.bde_crs_action_revision
  USING btree
  (_revision_expired);

CREATE INDEX idx_crs_action_expired_created
  ON table_version.bde_crs_action_revision
  USING btree
  (_revision_expired, _revision_created);

CREATE INDEX idx_crs_action_expired_key
  ON table_version.bde_crs_action_revision
  USING btree
  (_revision_expired, audit_id);


All of the table have been analysed before I tried to run the query.

The fact the all of the foreign keys have a covering index makes me wonder why this delete is taking so long.

The explain for

delete from table_version.revision where id = 1003


Delete  (cost=0.00..1.02 rows=1 width=6)
  ->  Seq Scan on revision  (cost=0.00..1.02 rows=1 width=6)
        Filter: (id = 100)

I'm running POstgreSQL 9.0.2 on Ubuntu 10.4

Cheers
Jeremy
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