I wrote:
> ISTM that getting rid of the division obviates the concern that the
> nentries condition is too expensive,
Also, we could make it slightly cheaper yet, by changing the condition
to
hctl->freeList[0].nentries > (long) (hctl->max_bucket)
ie drop the +1. I'd argue that this is actually a more faithful
rendition of the previous condition, since what we had before was
basically
hctl->freeList[0].nentries >= (long) (hctl->max_bucket + 1)
regards, tom lane