Thanks !
It works !!
-----Original Message-----
From: Bruno Wolff III [mailto:bruno@wolff.to]
Sent: Tuesday, July 13, 2004 1:59 PM
To: Eduardo Vázquez Rodríguez
Cc: Postgres (pgsql-novice@postgresql.org)
Subject: Re: [NOVICE] Query
On Tue, Jul 13, 2004 at 13:07:36 -0500,
Eduardo Vázquez Rodríguez <evazquez@insys-corp.com.mx> wrote:
> Hi I have a table called "master" which look like this
>
>
> id_master | month | day | infotype
> <Serial> PK | <Varchar 3> | <Varchar 3> | <Varchar 5>
> _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _
> 1 | May | 27 | 121
> 2 | May | 27 | 122
> 3 | May | 27 | 123
> 4 | May | 28 | 121
> 5 | May | 28 | 122
>
>
> Which Primary Key (id_master) is the Foreign Key (id_master) of
> another table called "masterdetail" which look like this
This is the problem infotype needs to be referenced, not id_master.
>
> id_masterdetail id_master argument color
> <Serial> PK | <int4> | <Varchar 30> | <Varchar 10>
> _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _
> 1 | 121 | house | blue
> 2 | 121 | house | blue
> 3 | 121 | building | white
> 4 | 122 | building | white
> 5 | 122 | house | yellow
>
>
> I try tu run a query to ask for all the arguments, which color has the
> value "blue" and they had the date "May" "27"
>
> I wrote something like this
>
> select argument from masterdetail, master where color like 'blue'
> and master.month like 'May'
> and master.day like '27'
> and master.id_master = masterdetail.id_master;
While eventually you want to change names and use '=' instead of 'like', for
the purposes of this question you want the last where condition to be:
and master.infotype = masterdetail.id_master::text;
>
>
> But I cant get the correct results!
>
> How can I fix it?
> ---
> Eduardo Vázquez Rodríguez <evazquez@insys-corp.com.mx> Insys
> Soluciones Integrales de Seguridad en TI Tel (52 55) 5322 5218
> Implantación
> ---
>
