Re: How to display an image (Image generation) - Mailing list pgsql-php

From Miguel Carvalho
Subject Re: How to display an image (Image generation)
Date
Msg-id 5854.213.13.176.13.1032944555.squirrel@www.ipatimup.up.pt
Whole thread Raw
In response to How to display an image (Image generation)  (arun kv <arun@library.iisc.ernet.in>)
List pgsql-php
Hi,

>        I am using the code
> <?php
> Header("Content-type: image/gif");
> $image = ImageCreate(100,50);
> $black = ImageColorAllocate($image,0,0,0);
> $white = ImageColorAllocate($image,255,255,255);
> ImageArc($image,50,25,48,0,$white);
> ImageGif($image);
> Imagedestroy($image);
> ?>
>   to display an image but the code is not working. how shud the code be
> and do i need to enable any libraries to do this. i have to get an
> image and get the midpoint(xy coordinate) of that image . how do i do
> that. if i run the above code i won't get any error but nothing will be
> displayed. how do i do this.

The previous code seams fine to me.

What version of GD are you using? If it's 1.6, as said in PHP docs

"Note:  Since all GIF support was removed from the GD library in version
1.6, this function is not available if you are using that version of the
GD library."
there wont be gif support.

Have you tried the same code using other formats, like jpeg, png?

Try sending the output to a file( use the second optional parameter to
imagegif, imagejpeg, etc) and check the file size.
Miguel




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