I copied over your typo :-), should be:
with recursive r as(
select ts, c, row_id from rnk where rnk.row_id = 1
union
select rnk.ts, rnk.c*0.33 + r.c*0.67, rnk.row_id
from
r
join
rnk
on
r.row_id = rnk.row_id - 1
),
rnk as(
select *, row_number() over(order by ts) row_id from tt
)
select ts, c from r order by ts;
Hello,
the table
create table tt (
ts timestamp,
c numeric) ;
insert into tt values
('2019-12-31',1), ('2020-01-01',2),
('2020-07-02',3), ('2020-07-06',4),
('2020-07-07',5), ('2020-07-08',6);
My question: It is possible to get an
additional column (named c2)
with
( c from current row ) + ( c2 from the previous row ) as c2
the result:
ts c c2
.. 1 1 -- or null in the first row
.. 2 3
.. 3 6
.. 4 10
...
with recursive ema as ()
select ts, c,
-- many many computed_rows
-- <code> as c2
from tt -- <- I need tt on this place
thank you for help
Franz
