John wrote:
> mytable
> pkid
> class_date.
> sessionid
>
> select * from mytable
> 1 2009/01/01 2101
> 2 2009/01/02 2101
>
> I would like an SQL that would produce
>
> newtable
> pkid,
> class_date1,
> class_date2,
> sessionid1,
> sessionid2
>
> Select * from newtable
>
> 1 2009/01/01 2009/01/02 2101 2101
>
> I have a list of classes that is perfect for our needs. However, I need to
> create the second table (from a query) to feed to a report writer so it can
> write out a single line of text for two records.
> Like:
>
> Your class dates are as follows
>
> Date Date
> 01/01/2009 01/02/2009
> 01/08/2009 01/10/2009
> 03/31/2009 04/05/2009
> and will continue until the all the classes are printed.
>
> The problem of course is the table has a row per class and the report writer
> needs two class dates per row.
>
> I have no idea how to do this using SQL.
>
> Thanks in advance,
> Johnf
>
Can you give a more precise example please? I don't get what you really
need. What I understand is that you want 1 record back for each
sessionid with the earliest and latest class_date.
I've done the following:
lem=# select * from mytable;pkid | class_date | sessionid
------+---------------------+----------- 1 | 2009-01-01 00:00:00 | 2101 2 | 2009-01-02 00:00:00 | 2101
3| 2009-01-01 00:00:00 | 2102 4 | 2009-01-02 00:00:00 | 2102 5 | 2009-01-01 00:00:00 | 2103 6 |
2009-01-0200:00:00 | 2103 7 | 2009-01-03 00:00:00 | 2103
(7 rows)
and then:
lem=# select min(pkid) as pkid
lem-# ,min(class_date) as class_date1
lem-# ,max(class_date) as class_date2
lem-# ,sessionid
lem-# from mytable
lem-# group by sessionid;pkid | class_date1 | class_date2 | sessionid
------+---------------------+---------------------+----------- 5 | 2009-01-01 00:00:00 | 2009-01-03 00:00:00 |
2103 3 | 2009-01-01 00:00:00 | 2009-01-02 00:00:00 | 2102 1 | 2009-01-01 00:00:00 | 2009-01-02 00:00:00 |
2101
(3 rows)
Is this what you need or is there something else? Can you give more
sample data and the result you expect from it?
Cheers, Leo
