Avoiding "will create implicit index" NOTICE - Mailing list pgsql-sql

From Bryce Nesbitt
Subject Avoiding "will create implicit index" NOTICE
Date
Msg-id 4A242CC4.5000400@obviously.com
Whole thread Raw
Responses Re: Avoiding "will create implicit index" NOTICE  (Scott Marlowe <scott.marlowe@gmail.com>)
List pgsql-sql
I'm looking for a good way to avoid triggering the "will create implicit 
index" NOTICE that Postgres (all versions) puts out.  This ends up 
spamming cron scripts for no good reason:

=> create table junk_six (foo int, primary key (foo));
NOTICE:  CREATE TABLE / PRIMARY KEY will create implicit index 
"junk_six_pkey" for table "junk_six"
CREATE TABLE

I've got a hacky solution (in perl), pulled from  
http://www.perlmonks.org/index.pl/jacques?node_id=540511
which suppresses the warning:

my $tmpwarn = $SIG{__WARN__};
$SIG{__WARN__} = sub { print STDERR @_ if $_[0] !~ m/NOTICE:  CREATE 
TABLE/; };
$sqldb->sql_execute("create table junk_six (foo int, primary key (foo));");
$SIG{__WARN__} = $tmpwarn;

And I know that I can edit the warning level in postgresql.conf with 
some other side effects.
But the best solution would be to avoid the notice in the first place.  
Is this possible?
       -Bryce

Keywords: postgres, warning, error, suppress, disable, avoid, hide, 
stderr, stdout


pgsql-sql by date:

Previous
From: Scott Marlowe
Date:
Subject: Re: Assigning data-entry tasks to multiple concurrent clients
Next
From: Scott Marlowe
Date:
Subject: Re: Avoiding "will create implicit index" NOTICE