ecpg-timestamp- interval problem V8.2.x - Mailing list pgsql-general

From paul tilles
Subject ecpg-timestamp- interval problem V8.2.x
Date
Msg-id 47FB75C1.8080209@noaa.gov
Whole thread Raw
Responses Re: ecpg-timestamp- interval problem V8.2.x  (Tom Lane <tgl@sss.pgh.pa.us>)
List pgsql-general
A colleague of mine is working with the following code (postgres Version
8.2.4):

#include <stdio.h>
#include <stdlib.h>
#include "pgtypes_timestamp.h"
#include "pgtypes_interval.h"

EXEC SQL INCLUDE sqlca;

main(argc, argv)
   int argc;
   char *argv[];
{
 timestamp dt1st, dt2nd;
 interval *int_day, *int_pt;

 char timebeg[40];
 char timeend[40];
 int rc;

 strcpy(timebeg,"2008-04-01");
 strcpy(timeend,"2008-04-05");

 printf("timebeg: %s\n", timebeg);
 printf("timeend: %s\n", timeend);

 dt1st=PGTYPEStimestamp_from_asc(timebeg,NULL);
 dt2nd=PGTYPEStimestamp_from_asc(timeend,NULL);
 int_day=PGTYPESinterval_from_asc("02 01:02:03", NULL);
 printf("int_day : %s\n", PGTYPESinterval_to_asc(int_day));

 rc=PGTYPEStimestamp_sub(&dt2nd, &dt1st, int_pt);
 printf("rc, date2 - date1 = %d, %s\n", rc, PGTYPESinterval_to_asc(int_pt));
 exit(0);
}

--------------------------------------------------------------------------------------------
The output is

timebeg: 2008-04-01
timeend: 2008-04-05
int_day : @ 2 days 1 hour 2 mins 3 secs
rc, date2 - date1 = 0, @ 1 sec ago

--------------------------------------------------------------------------------------------

The result of the subtraction of the the two timestamps is not correct.


What's going on?

TIA.

Paul Tilles

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