Re: How to Substract Milliseconds from A timestamp(3) Field - Mailing list pgsql-novice

From Steve Crawford
Subject Re: How to Substract Milliseconds from A timestamp(3) Field
Date
Msg-id 453547AC.9010201@pinpointresearch.com
Whole thread Raw
In response to Re: How to Substract Milliseconds from A timestamp(3) Field  ("Brandon Aiken" <BAiken@winemantech.com>)
Responses Re: How to Substract Milliseconds from A timestamp(3) Field
List pgsql-novice
Brandon Aiken wrote:
> SELECT (end_time - interval '00:00:05') AS work_timestamp FROM mytable;



No, that will subtract 5 seconds, not 5 milliseconds. Just use subtract
'0.005 seconds'::interval:


select now(), now()-'0.005 seconds'::interval;
              now              |           ?column?
-------------------------------+-------------------------------
 2006-10-17 14:11:59.805446-07 | 2006-10-17 14:11:59.800446-07

Cheers,
Steve




>
> --
> Brandon Aiken
> CS/IT Systems Engineer
>
> -----Original Message-----
> From: pgsql-novice-owner@postgresql.org
> [mailto:pgsql-novice-owner@postgresql.org] On Behalf Of Lane Van Ingen
> Sent: Tuesday, October 17, 2006 2:33 PM
> To: pgsql-novice@postgresql.org
> Subject: [NOVICE] How to Substract Milliseconds from A timestamp(3)
> Field
>
> In PLPGSQL, does anyone know how to subtract MILLISECONDS from a field
> defined as timestamp(3), yielding another field defined as timestamp(3)?
>
> Have been trying interval, and conversion functions but no luck.
>
> Example: '2006-10-17 14:23:28.951'; subtract 5 milliseconds from a field
>
>    called mytable.end_time, and return the results to a field named
>    work_timestamp.
>
> work_timestamp := ????


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