A. Kretschmer wrote:
> Hi,
>
> I have a table like this:
>
> test=# select * from status_log ;
> id | status | t_start | t_end
> ----+--------+------------------------+------------------------
> 1 | 1 | 2006-01-20 23:00:00+01 | 2006-01-21 06:00:00+01
> 1 | 1 | 2006-01-21 06:00:00+01 | 2006-01-21 22:00:00+01
> 1 | 2 | 2006-01-21 22:00:00+01 | 2006-01-22 05:00:00+01
> 1 | 1 | 2006-01-22 05:00:00+01 | 2006-01-22 15:00:00+01
> 1 | 2 | 2006-01-22 15:00:00+01 | 2006-01-23 02:00:00+01
> (5 rows)
>
> Now i need for a particular intervall (one day or two days, entires
> days) the accumulated time for id=X and status=Y.
>
> Exampel:
>
> id=1, status=1, date=2006-01-21:
>
> from 00:00:00 - 06:00:00 and
> 06:00:00 - 22:00:00
>
> ===> 6 hours + 16 hours = 22 hours
OK - all untested...
First step - don't ask for a date, ask between two timestamptz's (which
I'll call t1, t2)
Then, define two functions: earlier(timestamptz, timesatmptz) and
later(...) as SQL functions using SELECT ... CASE
SELECT later(T1, t_start) AS lower_time earlier(T2, t_end) AS upper_time
FROM status_log
WHERE id = X AND status = Y AND ts_end >= T1 AND ts_start <= T2
;
Now (upper_time - lower_time) is the interval you want and summing them
will give you your answer.
Any help?
-- Richard Huxton Archonet Ltd
