> What's happen? I can't continue helping you without it.
Sorry this is later than expected, things got a bit around here.
I attached the code so that spacing is preserved. It's in VB6 and just
a text file. The first method works, but none of the others do. I've
made note of the error I receive as comments in the code. If there's
anything else you need, just let me know.
Thank you,
Adam
Dim dbc As ADODB.Connection
Dim cmd As ADODB.Command
Set dbc = New ADODB.Connection
dbc.Open "DSN=GALSTA Postgres;", UserID, Password
' Verify that the connection opened properly.
If dbc.State And adStateOpen Then
Debug.Print "Connected"
' This method works.
' dbc.Execute "Insert into CHAPTER (CHAPTERID, CHAPTERDESC) values (1,'test1')"
' Start the second method.
Set cmd = New ADODB.Command
Set cmd.ActiveConnection = dbc
cmd.CommandText = "Insert into CHAPTER (CHAPTERID, CHAPTERDESC) values (?,?)"
' Error on next line: Provider cannot derive parameter information and SetParameterInfo has not been called.
cmd.Parameters.Refresh
cmd.Parameters.Item(0).Value = 2
cmd.Parameters.Item(1).Value = "test2"
cmd.Execute
Set cmd = Nothing
' Start the third method.
Set cmd = New ADODB.Command
Set cmd.ActiveConnection = dbc
cmd.CommandText = "Insert into CHAPTER (CHAPTERID, CHAPTERDESC) values (?,?)"
Call cmd.Parameters.Append(cmd.CreateParameter("ID", adNumeric, adParamInput, 4))
Call cmd.Parameters.Append(cmd.CreateParameter("DESC", adVarChar, adParamInput, 80))
cmd.Parameters.Item(0).Value = 3
cmd.Parameters.Item(1).Value = "test3"
' Error on next line: Multiple-step OLE DB operation generated errors. Check each OLE DB status value, if
available.No work was done.
cmd.Execute
Set cmd = Nothing
' Start the fourth method.
Set cmd = New ADODB.Command
Set cmd.ActiveConnection = dbc
cmd.CommandText = "Insert into CHAPTER (CHAPTERID, CHAPTERDESC) values (?,?)"
Call cmd.Parameters.Append(cmd.CreateParameter("ID", adNumeric, adParamInput, 4, 4))
Call cmd.Parameters.Append(cmd.CreateParameter("DESC", adVarChar, adParamInput, 80, "test4"))
' Next line produces the same error as the third method.
cmd.Execute
Set cmd = Nothing
' Done
dbc.Close
End If
Set dbc = Nothing
