Is there some reason you can't do this:
SELECT DISTINCT date_part('year', uu.add_date), date_part('month', uu.add_date), date_part('day', uu.add_date)
FROM uus INNER JOIN ui ON uus.user_id=ui.id INNER JOIN uu ON ui.id=uu.user_id WHERE uus.x_id=1
ORDER BY uu.add_date DESC;
This might be faster, as you only have to sort on one field, and I think it should give the desired results
ogjunk-pgjedan@yahoo.com wrote:
>Hello,
>
>I am trying to select distinct dates and order them in the reverse
>chronological order. Although the column type is TIMESTAMP, in this
>case I want only YYYY, MM, and DD back.
>
>I am using the following query, but it's not returning dates back in
>the reverse chronological order:
>
>SELECT DISTINCT
> date_part('year', uu.add_date), date_part('month', uu.add_date),
> date_part('day', uu.add_date)
>
>FROM uus INNER JOIN ui ON uus.user_id=ui.id INNER JOIN uu ON
>ui.id=uu.user_id
>WHERE uus.x_id=1
>
>ORDER BY
>date_part('year', uu.add_date), date_part('month', uu.add_date),
>date_part('day', uu.add_date) DESC;
>
>
>This is what the above query returns:
>
> date_part | date_part | date_part
>-----------+-----------+-----------
> 2004 | 2 | 6
> 2004 | 4 | 20
>(2 rows)
>
>
>I am trying to get back something like this:
>2004 4 20
>2004 4 19
>2004 2 6
>...
>
>My query is obviously wrong, but I can't see the mistake. I was
>wondering if anyone else can see it. Just changing DESC to ASC, did
>not work.
>
>Thank you!
>Otis
>
>
>---------------------------(end of broadcast)---------------------------
>TIP 2: you can get off all lists at once with the unregister command
> (send "unregister YourEmailAddressHere" to majordomo@postgresql.org)
>
>
--
Edmund Bacon <ebacon@onesystem.com>
