A way to do this is:
Select GETFILE From (Select Min(DATETIME),SID From LOGS Group by SID) as MDT, LOGS L Where L.SID
=MDT.SID And L.DATETIME = MDT.DATETIME
But this fails if there are more than one row for a given SID/DATETIME pair
(doe you have a unique index on them?).
Alternatively, you could try:
Select (Select GETFILE From LOGS L Where L.SID = S.SID Order By DATETIME Asc Limit 1) as GETFILE
From (Select Distinct SID From LOGS) as S
...the FROM statement would be a lot nicer if your had a table of SIDs, or
at least had a good way of generating the list of SIDs.
[Not sure if I got the PG dialect right]
At 18:03 26/07/01 -0400, Jeff Barrett wrote:
>
>Logs table has a primary key of logid (int4) and serveral columns, of which
>I am deling with sid (text), getfile (text), and datetime (int4). Now a
>select getfile, datetime, logid from logs where sid = onevalue; would return
>a set of rows for that sid, the row I want is for the one with the smallest
>aka min(datetime) and I want this for every row in the table.
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