On 22.08.24 09:34, Richard Guo wrote:
> I looked into this a little bit and found that in function
> create_ordered_paths, we decide whether a projection step is needed
> based on a simple pointer comparison between sorted_path->pathtarget
> and final_target.
>
> /* Add projection step if needed */
> if (sorted_path->pathtarget != target)
> sorted_path = apply_projection_to_path(root, ordered_rel,
> sorted_path, target);
>
> This does not seem right to me, as PathTargets are not canonical, so
> we cannot guarantee that two identical PathTargets will have the same
> pointer. Actually, for the query above, the two PathTargets are
> identical but have different pointers.
>
> I wonder if we need to invent a function to compare two PathTargets.
Wouldn't the normal node equal() work?