Re: BUG #16293: postgres segfaults and returns SQLSTATE 08006 - Mailing list pgsql-bugs

From Tom Lane
Subject Re: BUG #16293: postgres segfaults and returns SQLSTATE 08006
Date
Msg-id 28203.1583878791@sss.pgh.pa.us
Whole thread Raw
In response to BUG #16293: postgres segfaults and returns SQLSTATE 08006  (PG Bug reporting form <noreply@postgresql.org>)
Responses Re: BUG #16293: postgres segfaults and returns SQLSTATE 08006  (Daniel WM <dwilches@gmail.com>)
List pgsql-bugs
PG Bug reporting form <noreply@postgresql.org> writes:
> I finally found the issue was that one of the tests was trying to insert a
> row on a partitioned table, but there was no partition where to put that
> row, so it had to go to the default partition. But, the default partition
> had a constraint that disallowed that row, so the row couldn't be inserted
> and Postgres ended with a segfault.

Hm, works for me:

regression=# create table tt (f1 int, f2 text) partition by list(f1);
CREATE TABLE
regression=# create table t1 partition of tt for values in (1);
CREATE TABLE
regression=# create table tother partition of tt default;
CREATE TABLE
regression=# alter table tother add check (length(f2) > 1);
ALTER TABLE
regression=# insert into tt values (1, 'f');
INSERT 0 1
regression=# insert into tt values (3, 'f');
ERROR:  new row for relation "tother" violates check constraint "tother_f2_check"
DETAIL:  Failing row contains (3, f).
regression=#

Admittedly this is v11 branch tip not exactly 11.7, but I don't see
anything related-looking in the commit log.  So I think there is some
contributing factor you didn't mention.  Could you provide a
self-contained reproduction script?

            regards, tom lane



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