On 1/27/22 10:03, Merlin Moncure wrote:
On Wed, Jan 26, 2022 at 5:23 PM Merlin Moncure <mmoncure@gmail.com> wrote:
with s as (select 'Hello World Hello World' as sentence)
select phrase, array_upper(string_to_array((select sentence from s), phrase), 1) -
1 as occurrances
from
( select array_to_string(x, ' ') as phrase from ( select distinct v[a:b] x from regexp_split_to_array((select sentence from s), ' ') v cross join lateral generate_series(1, array_upper(v, 1)) a cross join lateral generate_series(a + 1, array_upper(v, 1)) b ) q
) q;
Simplified to:
select distinct array_to_string(v[a:b], ' ') phrase, count(*) as occurrences
from regexp_split_to_array('Hello World Hello World', ' ') v
cross join lateral generate_series(1, array_upper(v, 1)) a
cross join lateral generate_series(a + 1, array_upper(v, 1)) b
group by 1;
phrase │ occurances
─────────────────────────┼──────────── World Hello │ 1 Hello World Hello │ 1 Hello World │ 2 Hello World Hello World │ 1 World Hello World │ 1
merlin
And since we're looking for repeated phrases maybe add
having count(*) > 1
