Re: Given 02-01-2006 to 02-28-2006, output all days. - Mailing list pgsql-sql

Pedro,

Would something such as this suffice?

Mark

create function get_date_range(date, date) returns setof date as '
DECLARE
    cur date;
BEGIN
    cur := $1;

    while cur <= $2 LOOP
         return next cur;
         cur := cur + interval ''1 day'';
    end LOOP;
    return;
END;' language 'plpgsql';

dev=# select * from get_date_range('2/1/2006'::date, '2/28/2006'::date);
 get_date_range
----------------
 2006-02-01
 2006-02-02
 2006-02-03
 2006-02-04
 2006-02-05
 2006-02-06
 2006-02-07
 2006-02-08
 2006-02-09
 2006-02-10
 2006-02-11
 2006-02-12
 2006-02-13
 2006-02-14
 2006-02-15
 2006-02-16
 2006-02-17
 2006-02-18
 2006-02-19
 2006-02-20
 2006-02-21
 2006-02-22
 2006-02-23
 2006-02-24
 2006-02-25
 2006-02-26
 2006-02-27
 2006-02-28
(28 rows)

On Monday 20 February 2006 15:30, Pedro B. wrote:
> Hello.
> I'm having difficulties on my first incursion through generate_series.
>
> The details:
>
> SELECT DATE_TRUNC('month', timestamp '2006-02-01' )::DATE + s.d AS date,
>       COUNT (o."04-sms") as totalcause98
>       FROM generate_series(11,19) AS s(d)
>  LEFT JOIN netopia o ON (substr(o."26-insertTime",1,10) =
> (DATE_TRUNC('month', timestamp'2006-02-01'  )::DATE + s.d) andcreate
function get_date_range(date, date) returns setof date as '
DECLARE   cur date;
BEGIN   cur := $1;
   while cur <= $2 LOOP        return next cur;        cur := cur + interval ''1 day'';   end LOOP;   return;
END;' language 'plpgsql';

dev=# select * from get_date_range('2/1/2006'::date, '2/28/2006'::date);get_date_range

----------------2006-02-012006-02-022006-02-032006-02-042006-02-052006-02-062006-02-072006-02-082006-02-092006-02-102006-02-112006-02-122006-02-132006-02-142006-02-152006-02-162006-02-172006-02-182006-02-192006-02-202006-02-212006-02-222006-02-232006-02-242006-02-252006-02-262006-02-272006-02-28
(28 rows)
> o.cause01=98)
>  GROUP BY s.d ORDER BY 1;
>
>
> This query (although quite messed up on the date parameters), does exactly
> what i want:
> "sum column 'cause01=98' for a specified date range, including 0's"
>
>     date    | totalcause98
> ------------+--------------
>  2006-02-12 |            0
>  2006-02-13 |            0
>  2006-02-14 |            0
>  2006-02-15 |            0
>  2006-02-16 |           68
>  2006-02-17 |          256
>  2006-02-18 |          104
>  2006-02-19 |           34
>  2006-02-20 |           20
>
> I'm using a left join because i really need the =0 sums.
> The use of substr() is due to the fact the "26-insertTime" on the 'netopia'
> table has a default of 'default (now())::timestamp(2) without time zone'.
> So, i can make generate_series work with the left join using the substr.
> I was getting ready to optimize this query, when i remembered i also have
> the need for another column, 'totalcause99', almost the same as this query,
> but with 'cause01=99' as condition.
>
> The maximum i was able to do without syntax errors was:
>
> SELECT DATE_TRUNC('month', timestamp '2006-02-01' )::DATE + s.d AS date,
>       COUNT (o."04-sms") as totalcause98,
>       COUNT (p."04-sms") as totalcause99
>       FROM generate_series(11,19) AS s(d)
>  LEFT JOIN netopia o ON (substr(o."26-insertTime",1,10) =
> (DATE_TRUNC('month', timestamp'2006-02-01'  )::DATE + s.d) and
> o.cause01=98)
>  LEFT JOIN netopia p ON (substr(p."26-insertTime",1,10) =
> (DATE_TRUNC('month', timestamp'2006-02-01'  )::DATE + s.d) and
> p.cause01=99)
>  GROUP BY s.d ORDER BY 1;
>
> Reading this one aloud, i feel the "logic" of what i'm trying to do, but
> the values of its output are.. scary to say the least, and the sums are
> exactly the same on the 2 columns, and that should never happen with the
> data i have on the table.
>
> I'm starting to wonder if this is actually possible to be done on one
> single query...
> Ideas, anyone?
>
> Sorry for the long email.
> Any and all help is deeply appreciated.
>
> Regards,