On Thu, Oct 30, 2003 at 08:24:13PM +0100, Jeroen T. Vermeulen wrote:
>
> Then the whole loop could become something like this:
Okay, that code wasn't entirely correct but it gets the idea across. In
C++ terms, what I arrived at was:
string result; for (int i=0; i<F.size(); ++i) { unsigned char c = p[i]; if (c == '\\') { c = p[++i]; if
(isdigit(c)&& isdigit(p[i+1]) && isdigit(p[i+2])) {c = (VAL(p[c])<<9) | (VAL(p[i+1])<<3) | VAL(p[i+2]);i += 2;
} } result += char(c); }
Simple, no?
Jeroen
