On Mon, Dec 02, 2002 at 12:18:37PM -0500, Joel Burton wrote:
> insert into train (depart,arrive) values ('2002-01-01 1:00
> PM','2002-01-01 2:00 PM');
>
> insert into trains (depart,arrive) values ('2002-01-01 1:00
> PM','2002-01-01 2:00 PM');
>
> insert into trains (depart,arrive) values ('2002-01-01 4:00
> PM','2002-01-01 5:00 PM');
>
> insert into trains (depart,arrive) values ('2002-01-02 4:00
> PM','2002-01-01 5:00 PM');
>
> insert into trains (depart,arrive) values ('2002-01-02 4:00
> PM','2002-02-01 5:00 PM');
>
> insert into trains (depart,arrive) values ('2002-01-09 4:00
> PM','2002-02-09 5:00 PM');
>
>
> joel@joel=# select * from trains;
> id | depart | arrive
> ----+---------------------+---------------------
> 1 | 2002-01-01 13:00:00 | 2002-01-01 14:00:00
> 2 | 2002-01-01 16:00:00 | 2002-01-01 17:00:00
> 4 | 2002-01-02 16:00:00 | 2002-02-01 17:00:00
> 5 | 2002-01-09 16:00:00 | 2002-02-09 17:00:00
>
>
> Ok, so trains 2 and 4 have arrivals where the last departure is more
> than 7 hours away. And train 5 will also appear, since there is no
> departure after it.
...
> And we get train #1, which is the earliest train arrival that meets the
> requirements.
Eek! Need to get lunch before brain falls asleep. Train #3 disappeared
into a derailed insert statement, so if you cut & paste my data, your
trains 3 & 4 will be my 4 & 5.
And train #2, not #1, is the ultimate answer.
--
Joel BURTON | joel@joelburton.com | joelburton.com | aim: wjoelburton
Independent Knowledge Management Consultant
