remove the as in "date_larger(m.effdt, q.effdt) as
effdt)::float8" on the line you marked
Jim
> Howdy:
>
> Running Postgres 7.1.3 on RedHat Linux 7.2, kernel
2.4.7-rel 10.
>
> Have an SQL question, which may very well be that
> I need a second pair of eyes to trouble shoot the script.
>
> [script]
> explain
> select
> q.qid,
> q.year,
> m.contract,
> m.mbr_num,
> m.bu,
> m.mbr_sex,
> m.product,
> m.prov_num,
> m.riskgrp,
> p.c_spec_1 as spec,
> date_larger(m.effdt, q.effdt) as effdt,
> date_smaller(m.enddt, q.enddt) as enddt,
> -->>> (date_smaller(m.enddt, q.enddt) as enddt -
> date_larger(m.effdt, q.effdt) as effdt)::float8 / 30.4 as
memmonth <<<--
> from members m,
> product p,
> quarters q
> where
> m.prov_num=p.c_prov_num
>
> --------- make sure *all* the spans overlap one
another ----
> and not (
> m.enddt < q.effdt
> or m.effdt > q.enddt
> )
> ;
> [/script]
>
> I believe the problem comes from what's marked off by
> the arrows. The error I get from this is:
>
> ERROR: parser: parse error at or near "as"
>
> If I comment that out, things work. It *used* to work
> before, but for the life of me, I don't recall changing
> anything ...
>
> Where is the syntax error?
>
> Thanks!
>
> -X
