chester c young wrote:
> thanks, but how would this be done for the same table?
>
> update table1 t1 set (c2, c3 ) =
> ( select c2, c3 from table1 t2 where t1.c1 = t2.c1 and t1.oid < t2.oid
> );
In that 'FROM c1 c2', c2 was a table alias for table c1. That is how
you get the second instance of c1.
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