On Mon, 17 Dec 2001, MindTerm wrote:
> select count(*)
> from ACL a, APPLICATION app
> where ACL_APP = app.app_id
> and APP_INSTALLED = 'Y'
> and ACL_LEVEL > 0
> and ACL_GALLERY_ID = 1
> and app.APP_GALLERY_ID = 1
> and substr(app.app_order,1, 6 ) = '021101'
> and app.app_order <> '021101'
> and exists
> (select u.ug_id
> from user_group u, user_group_master
> ug
> where a.ACL_GRP = u.ug_id
> and u.ug_user_id = 5170
> and ug.ug_id = u.ug_id
> and (ug.deleted = 'N' or ug.deleted
> IS NULL)
> and u.gallery_id = 1
> and ug.gallery_id = 1 );
I don't know if it'll help, but does:
select count(*)from ACL a, APPLICATION app, user_group u,user_group_master ug where ACL_APP =
app.app_id and APP_INSTALLED = 'Y' and ACL_LEVEL > 0 and ACL_GALLERY_ID = 1
and app.APP_GALLERY_ID = 1 and substr(app.app_order,1, 6 ) = '021101' and app.app_order
<>'021101' and a.ACL_GRP = u.ug_id and u.ug_user_id = 5170 and ug.ug_id
=u.ug_id and (ug.deleted = 'N' or ug.deletedIS NULL) and u.gallery_id = 1
and ug.gallery_id = 1;
give the same results as the original query. Maybe
that form will work faster. (I'm going to play with
it a little tomorrow, but since I don't have much data
in there, I'm not sure how well it'll translate)
