See the updated FAQ on our web site for syntax.
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> <html><head></head><body>Using the example:<br>
> SELECT '' AS "xxx", *<br>
> FROM J1_TBL LEFT OUTER JOIN J2_TBL USING (i);<br>
> <br>
> ..doesn't work because the columns which I am using to join the tables don't
> have the same name. How do i specify the columns if they don't have the same
> name?<br>
> <br>
> Poul L. Christiansen<br>
> <br>
> Tom Lane wrote:<br>
> <blockquote type="cite" cite="mid:6858.976116402@sss.pgh.pa.us"><pre wrap="">"Poul L. Christiansen" <a
class="moz-txt-link-rfc2396E"href="mailto:poulc@cs.auc.dk"><poulc@cs.auc.dk></a> writes:<br></pre>
> <blockquote type="cite"><pre wrap="">But how do I make an outer join? <br>What's the syntax?<br>I will RTFM if
someonepoints me to the docs :-)<br></pre></blockquote>
> <pre wrap=""><!----><br>I'm afraid I haven't updated the FM yet :-( ... but you could look at<br>the examples in
theJOIN regress test, src/test/regress/sql/join.sql.<br><br>Or, from the SQL92 spec, here's the grammar:<br><br>
<from clause> ::= FROM <table reference> [ { <comma> <table reference> }... ]<br><br>
<tablereference> ::=<br> <table name> [ [ AS ] <correlation name><br>
[ <left paren> <derived column list> <right paren> ] ]<br> | <derived table> [ AS
]<correlation name><br> [ <left paren> <derived column list> <right paren>
]<br> | <joined table><br><br> <derived table> ::= <table subquery><br><br>
<derived column list> ::= <column name list><br><br> <column name list> ::=<br>
<columnname> [ { <comma> <column name> }...
> </blockquote>
> <br>
> </body></html>
>
>
>
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